一、给定一个日期值，求出此日期所在星期的星期一和星期天的日期数据
例如给定一个日期 2010-09-01，求出它所在星期的星期一是2010-08-30，星期天是2010-09-05

Function创建如下:

复制代码 代码如下:

USE [MSSQL]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[My_OneDay_GetWeekFirstAndEndDay](@tmpDate DATETIME)
RETURNS @tmpTable TABLE(FirstDay DATETIME , EndDay DATETIME)
AS
BEGIN
INSERT INTO @tmpTable
SELECT a.FirstDay,b.EndDay FROM (
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy
) a
LEFT JOIN (
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay
) b
ON a.ID = b.ID
RETURN
End

复制代码 代码如下:

SELECT * from My_OneDay_GetWeekFirstAndEndDay('2010-09-01')

复制代码 代码如下:

USE [MSSQL]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[MY_Range_GetWeekFirstAndEndDays](@tmpDateSTART DATETIME,@tmpDateEND DATETIME)
RETURNS @tmpTable TABLE(WeekOrder INT,FirstDay DATETIME , EndDay DATETIME)
AS
BEGIN
DECLARE @tmpDate DATETIME
DECLARE @index INT
SET @tmpDate=@tmpDateSTART
SET @index=1
WHILE @tmpDate <=@tmpDateEND
BEGIN
INSERT INTO @tmpTable
SELECT @index,a.FirstDay,b.EndDay FROM (
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy) a
LEFT JOIN (
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay) b
ON a.ID = b.ID

SET @tmpDate=DATEADD(DAY,7,@tmpDate)
SET @index=@index+1
END
RETURN
End

复制代码 代码如下:

SELECT * from My_Range_GetWeekFirstAndEndDays('2011-09-01','2011-10-06')